Posts Tagged ‘Java Tutorials for Beginners’
Using For Each in Java
Posted on: April 2, 2020
Objective:
- How to use For Each in Java?
- How to use advance for in Java?
- How to use advance for loop in Java Programming Language?
- Types of For loop in Java
Source Code:
class ForEachExample
{
public static void main(String args[])
{
//declaring an array
int a[]={1,2,3,4,5,6};
// Old way
System.out.println("Old way");
for(int i=0; i<a.length;i++)
{
System.out.println(a[i]);
}
//New way: for-each loop
System.out.println("For each");
for(int i:a)
{
System.out.println(i);
}
}
}
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Pattern 2 :
1
2 2
3 3 3
4 4 4 4
5 5 5 5 5
Java Program for the above pattern:
import java.util.Scanner;
public class MainClass
{
public static void main(String[] args)
{
Scanner sc = new Scanner(System.in);
//Taking rows value from the user
System.out.println("How many rows you want in this pattern?");
int rows = sc.nextInt();
System.out.println("Here is your pattern....!!!");
for (int i = 1; i <= rows; i++)
{
for (int j = 1; j <= i; j++)
{
System.out.print(i+" ");
}
System.out.println();
}
//Close the resources
sc.close();
}
}
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Objectives :
- Convert Decimal number to Roman number
- Convert Decimal numeral to Roman numeral
- How to convert a decimal number to roman number
- Write a program that converts a decimal number to Roman number.
- Write a program that converts a decimal number to Roman number. Decimal Number is accepted using Scanner class at the time of execution.
- Write a program that converts a decimal number to Roman number. Decimal Number is accepted as command line input at the time of execution.
Program :
Java program that converts a decimal number to Roman number. Decimal Number is accepted using Scanner class at the time of execution.
import java.util.Scanner;
public class DecimalToRoman {
private static String toRoman(int num) {
String[] romanCharacters = { "M", "CM", "D", "C", "XC", "L", "X", "IX", "V", "I" };
int[] romanValues = { 1000, 900, 500, 100, 90, 50, 10, 9, 5, 1 };
String result = "";
for (int i = 0; i < romanValues.length; i++) {
int numberInPlace = num / romanValues[i];
if (numberInPlace == 0) continue;
result += numberInPlace == 4 && i > 0? romanCharacters[i] + romanCharacters[i - 1]:
new String(new char[numberInPlace]).replace("\0",romanCharacters[i]);
num = num % romanValues[i];
}
return result;
}
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("Enter a number : ");
int decimal = scanner.nextInt();
System.out.println(toRoman(decimal));
}
}
Output :
Enter a number : 1234
MCCXXXIV
Java program that converts a decimal number to Roman number. Decimal Number is accepted as command line input at the time of execution.
public class DecimalToRoman {
private static String toRoman(int num) {
String[] romanCharacters = { "M", "CM", "D", "C", "XC", "L", "X", "IX", "V", "I" };
int[] romanValues = { 1000, 900, 500, 100, 90, 50, 10, 9, 5, 1 };
String result = "";
for (int i = 0; i < romanValues.length; i++) {
int numberInPlace = num / romanValues[i];
if (numberInPlace == 0) continue;
result += numberInPlace == 4 && i > 0? romanCharacters[i] + romanCharacters[i - 1]:
new String(new char[numberInPlace]).replace("\0",romanCharacters[i]);
num = num % romanValues[i];
}
return result;
}
public static void main(String[] args) {
if(args.length<1 || args.length>1){
System.out.println("Wrong input");
}else{
String number = args[0];
int decimal = Integer.parseInt(number);
System.out.println(toRoman(decimal));
}
}
}
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Objectives :
- Decimal to Binary Conversion
- Converting Decimal to Binary
- Converting Decimal Number to Binary format
- Write a program to convert decimal to binary
- Write a program to convert decimal number to binary format
- Write a program to convert positive decimal number to binary format
- Write a program to convert decimal to binary using Scanner class
- Write a program to convert decimal to binary, take input using Scanner class
Java Program to convert Decimal to Binary :
public class DecimalToBinary {
public void toBinary(int number){
int binary[] = new int[25];
int n = 0;
// Convert Decimal to Binary
while(number > 0){
binary[n++] = number%2;
number = number/2;
}
// Print Binary number
for(int i = n-1;i >= 0;i--){
System.out.print(binary[i]);
}
}
public static void main(String[] args){
DecimalToBinary obj = new DecimalToBinary();
obj.toBinary(14);
}
}
Output :
1110
Java Program to convert Decimal to Binary using Scanner class :
import java.util.Scanner;
public class DecimalToBinary {
public void toBinary(int number){
int binary[] = new int[14];
int n = 0;
// Convert Decimal to Binary
while(number > 0){
binary[n++] = number%2;
number = number/2;
}
// Print Binary Number
for(int i = n-1;i >= 0;i--){
System.out.print(binary[i]);
}
}
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("Enter a number: ");
int num= scanner.nextInt();
DecimalToBinary obj = new DecimalToBinary();
obj.toBinary(num);
}
}
Output :
Enter a number: 14
1110
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Objectives :
- Write a Java program to find prime number upto N number
- Write a Java program to print prime number upto N number
- Write a Java program to find prime number upto N number using Command Line Arguments
- Write a Java Program to find prime number upto N number via Command Line Arguments
- Write a Java program to find prime number upto N number using Scanner class
Java Program / Code :
Method 1 : Java Program to find Prime Number upto N number using Scanner class
import java.util.Scanner;
class PrimeNumber
{
public static void main(String[] args)
{
int n,p;
Scanner s=new Scanner(System.in);
System.out.println(“Enter number : ”);
n=s.nextInt();
for(int i=2;i<n;i++)
{
p=0;
for(int j=2;j<i;j++)
{
if(i%j==0)
p=1;
}
if(p==0){
System.out.println(i);
}
}
}
}
Method 2 : Java Program to find Prime Number upto N number using Scanner class and writing function to find prime number
Method isPrime() for checking if a number is prime or not
public class PrimeNumber{
public boolean isPrime(int num) {
if ( num < 2 ){
return false;
}
for (int i = 2; i <= Math.sqrt(num); i++) {
if ( num % i == 0 ) {
return false;
}
}
return true;
}
}
// Mock Test Class to test above code
import java.util.Scanner;
public class Demo
{
public static void main(String[] args)
{
Scanner scanner = new Scanner(System.in);
System.out.println("Please enter a number: ");
int num = scanner.nextInt();
if ( num < 2 ) {
System.out.println("\n There are no Prime Numbers available");
System.exit(0);
}
System.out.println("\n Prime Numbers from 1 to "+ num);
PrimeNumber primeNum = new PrimeNumber();
for (int i = 3; i <= num; i++) {
if ( primeNum.isPrime(i) ) {
System.out.print(", " + i);
}
}
}
}
Method 3 : Java Program to find Prime Number upto N number using Command line input
class PrimeNumber
{
public static void main(String[] args)
{
int n,p;
n=Integer.parseint(args[0]);
for(int i=2;i<n;i++)
{
p=0;
for(int j=2;j<i;j++)
{
if(i%j==0)
p=1;
}
if(p==0){
System.out.println(i);
}
}
}
}
Steps to run above program via command line :
- Compilation : C:\JavaPrograms>javac PrimeNumber.java
- Interpretation : C:\JavaPrograms>java PrimeNumber 20
Output :
2
3
5
7
11
13
17
19
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